如何在不使用globals的情况下影响python生成器：timeexamp

Question

我试图在运行时影响生成器。这段代码使用一个全局函数，我要求用一种更具pythonic风格的方法来获得相同的结果。你知道吗

本例打印出时间范围内的小时和分钟。应该跳过13:15到15:45的范围（这是一个示例，在现实世界中，跳过某些值的决定不是固定的）

我可以用更好的方法将全局skiptime传递给生成器吗？你知道吗

import datetime

globalskiptime = None


def mynexttime(mystart=None):
    # returns 15 30 45 59 minute for each hour
    for myhour in range(0, 24):
        for myminute in range(15, 61, 15):
            if mystart is not None:
                if datetime.time(myhour, myminute
                                 if myminute < 60 else 59) < mystart:
                    continue
            if globalskiptime is not None:
                if datetime.time(myhour, myminute
                                 if myminute < 60 else 59) < globalskiptime:
                    continue
            yield myhour, myminute if myminute < 60 else 59


mystarttime = datetime.time(10, 45)

print type(mystarttime) is datetime.time

for h, m in mynexttime(mystarttime):
    print(str(h) + " " + str(m))
    if h == 13:
        print('skip until 15:45')
        globalskiptime = datetime.time(15, 45)

Answer 1

在@VincentSavard提示之后，我重写了代码以使用send()将数据发送到生成器。我不得不在最后放弃for循环，但是在运行时更改for循环是很困难的。你知道吗

这就是我的目的：

import datetime

def mynexttime(mystart=None):
    # returns 15 30 45 59 minute for each hour
    for myhour in range(0, 24):
        for myminute in range(15, 61, 15):
            if mystart is not None:
                if datetime.time(myhour, myminute
                                 if myminute < 60 else 59) < mystart:
                    continue
            mystart = (yield myhour, myminute if myminute < 60 else 59)

# start at 12:45
mytest = mynexttime(datetime.time(12, 45))

breaktime = None
while True:
    try:
        h, m = mytest.send(breaktime)
        print(str(h) + ":" + str(m))
        if h == 13:
            breaktime = datetime.time(15, 44)
            print('skip until 15:45')
    except StopIteration:
        break