如何从带有数字的字符串中去掉字母，以便可以将其更改为int并进行排序

Question

我正在做一个掷骰子游戏，其中的分数和球员必须存储在一个数组，然后打印出来，作为记分牌的顺序。我可以做所有这些，但排序记分牌。你知道吗

我已经计算出我需要从字符串中去掉字母（player1 37到just 37）。我目前使用的代码是delchars = Player1.join(c for c in map(chr, range(256)) if not c.isalnum())，但它似乎不起作用，任何人都知道该怎么做。你知道吗

#code for entering Player1 
let= True
while let == True:
    delay_print("player 1 enter your username\n")
    Player1 = input()
    if len(Player1) > 20 or len(Player1) < 3:
        print("That is too long or too short, please try again") 
    else:
        let = False
#code for entering Player2
tel = True
while tel == True:
    delay_print("player 2 enter your username\n")
    Player2 = input()
    if len(Player2) > 20  or len(Player2) < 3:
        print("That is too long, or too short, please try again")
    else:
        tel = False

我期望的结果是能够打印出一个记分板，顺序。 此记分牌的当前代码为

print("first place is ", scoreboard[0] ,
      "\nsecond place is ", scoreboard[1], 
      "\nthird place is "  ,scoreboard[2], 
      "\nfourth place is " ,scoreboard[3], 
      "\nfifth place is "  ,scoreboard[4])

Answer 1

而不是

delchars = Player1.join(c for c in map(chr, range(256)) if not c.isalnum())

使用

delchars = "".join([c for c in Player1 if not c.isalnum()])