擅长:python、mysql、java
<p>试试这个:</p>
<pre><code>from collections import defaultdict
issuelist = [["k1","v1"],["k2","v2"],["k3","v1"],["k4","v2"],["k5","v2"],["k6","v3"],["k7","v1"]]
result = defaultdict(list)
for inner_list in issuelist:
result[inner_list[1]].append(inner_list[0])
result_array = list(result.values())
rint(presult_array)
</code></pre>