我写了一个函数来创建一个域来收集进入探测器的光的强度。当我使用一个单一的值作为起始点是可以的,但是当我设置一个poitns数组时(因为我需要描述一个曲面并将强度积分到这个曲面上),它会引发ValueError:用序列设置一个数组元素。你知道吗
我试着验证不同数组的形状和它(3,)和(3,),所以在理论上没有不一致。。。这里是函数
def probe_intensity(cone_FOV, n_circles):
probeI = 0
# probe location information
#probe_angle = 5.0/4.0*np.pi
#tvar=np.linspace(4.09,4.186,30)
ray_cone_angle = cone_FOV/(2.0*n_circles)
# T0 = np.array([0, 0, 1])
r = 6.2
x = 5.5
probe_angle = np.linspace(1.2334*np.pi-1,1.2334*np.pi+1,30)
probe_direction_angle = probe_angle - np.pi
#R1=np.ones(len(probe_angle))
# probe direction
for k in probe_angle:
# getting the estimated cone for a single ray
#ray_cone_angle = cone_FOV/(2.0*n_circles)
# probe position information
#r = 6.2
#x = 5.5
R0 = np.array([5.5,
r*np.sin(probe_angle)+0.0001,
r*np.cos(probe_angle)+0.0001])*0.001
gamma = probe_direction_angle
ROT1 = np.matrix([[1, 0, 0],
[0, np.cos(gamma), np.sin(gamma)],
[0, -np.sin(gamma), np.cos(gamma)]])
# vector T0 before any rotation
T0 = np.array([0, 0, 1])
# vector T1 - probe axis vector
T1 = np.array(ROT1*np.matrix(T0).T).flatten()
# rotation for the cone_half_angle
for ray_carrier_angle in [(i + 0.5)*ray_cone_angle for i in range(n_circles)]:
alpha = ray_carrier_angle
ROT2 = np.matrix([[np.cos(alpha), 0, np.sin(alpha)],
[0, 1, 0],
[-np.sin(alpha), 0, np.cos(alpha)]])
# rotating to make a full circle of the cone
for beta in np.linspace(0, 2*np.pi, int(np.round(n_circles*np.pi))):
ROT3 = np.matrix([[np.cos(beta), np.sin(beta), 0],
[-np.sin(beta), np.cos(beta), 0],
[0, 0, 1]])
# second rotaiton for the cone after the probe direction rotation
T3 = np.array(ROT1*ROT3*ROT2*np.matrix(T0).T).flatten()
print R0
print R0.shape
print T3
print T3.shape
T3=list(T3)
R0=list(R0)
ray_solution = ray_trace_solve_ivp(R0, T3, 0.0005)
t, I = field.integrate_trace(ray_solution, 0.0005)
#s,e,alpha,I = field.getspectra
# Add the intensity of the ray to the intensity gathered at the probe. Dot product takes care of the projection
probeI += I[-1]*np.dot(T0, T3)
print probeI
return probeI
另一个被调用的函数是
def ray_trace_solve_ivp(R0, T0, optical=False, dt=np.inf, atol=1e-6, rtol=1e-2):
y0 = np.r_[R0, T0]
if optical:
differential_equation = eikonalODE1system_optical
else:
differential_equation = eikonalODE1system_physical
sol = solve_ivp(differential_equation, [0, 0.5], y0,
events=limit_functions,
dense_output=True,
max_step=dt,
atol=atol,
rtol=rtol)
return sol
我收到以下错误消息:
File "/home/tont_fe/anaconda2/lib/python2.7/site-packages/spyder_kernels/customize/spydercustomize.py", line 827, in runfile execfile(filename, namespace) File "/home/tont_fe/anaconda2/lib/python2.7/site-packages/spyder_kernels/customize/spydercustomize.py", line 102, in execfile builtins.execfile(filename, *where) File "/home/tont_fe/data/cfd/OH_analysis/OHstar_ray_tracing/oh_ray_trace_candidate_cone_federica.py", line 1109, in print("probe intensity=", probe_intensity(np.pi/20.0, 10)) File "/home/tont_fe/data/cfd/OH_analysis/OHstar_ray_tracing/oh_ray_trace_candidate_cone_federica.py", line 878, in probe_intensity ray_solution = ray_trace_solve_ivp(R0, T3, 0.0005) File "/home/tont_fe/data/cfd/OH_analysis/OHstar_ray_tracing/oh_ray_trace_candidate_cone_federica.py", line 690, in ray_trace_solve_ivp rtol=rtol) File "/home/tont_fe/anaconda2/lib/python2.7/site-packages/scipy/integrate/_ivp/ivp.py", line 456, in solve_ivp solver = method(fun, t0, y0, tf, vectorized=vectorized, **options) File "/home/tont_fe/anaconda2/lib/python2.7/site-packages/scipy/integrate/_ivp/rk.py", line 96, in __init__ support_complex=True) File "/home/tont_fe/anaconda2/lib/python2.7/site-packages/scipy/integrate/_ivp/base.py", line 120, in __init__ self._fun, self.y = check_arguments(fun, y0, support_complex) File "/home/tont_fe/anaconda2/lib/python2.7/site-packages/scipy/integrate/_ivp/base.py", line 15, in check_arguments y0 = y0.astype(dtype, copy=False)
因此,代码的相关部分是:
或者简化一点:
您的
R0
,然后是y0
构造函数,生成一个对象数据类型数组—一个包含数组的数组。你知道吗但是
solve_ivp
需要一个(n,)浮点数组,其中n
是differential_equation
产生的值的数目。你知道吗直接的问题是从
y0
创建一个数字数组。既然我不知道你需要或想要什么,我就不打算提出解决办法。你知道吗而且我对
differential_equation
一无所知。我不知道它能返回多少值。就一个,三个?或者它是否随y0
输入的大小而变化?你知道吗退一步,做一个更简单的问题。确保您了解
solve_ivp
的需求,包括函数和y0
。你知道吗当你带着新问题回来的时候,请让它更容易帮助你!你知道吗
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