我试图对一些文件进行排序,首先在dir
中找到文件名,例如glob.glob
(filename1,filename2,filename3),所以我得到了这个文件列表[(filename1,),(filename2,),(filename3,)]
在此之后,我有一个for循环,它用.readline()
从每个文件中提取一个字符串。所以在每个循环执行之后,filename1打印10个字符串,下一个循环filename2打印3个字符串,下一个循环filename3打印5个字符串。你知道吗
loop
[string1]
[string2]
[string3]
.....
loop
[string1]
[string2]
[string3]
....
loop
[string1]
[string2]
[string3]
....
问题是,我知道这10个字符串来自filename1,但我想指出它们确实来自filename1。你知道吗
How i would like it to look after print
loop
[filename1 , string1]
[filename1 , string2]
[filename1 , string3]
.......
new loop
[filename2 , string1]
[filename2 , string2]
[filename2 , string3]
.......
new loop
[filename3 , string1]
[filename3 , string2]
[filename3 , string3]
有人能帮我或送我到正确的方向吗?我搜索了“将一个列表分配给另一个列表中的元素”和类似的标签,但是找不到我需要的。。。谢谢你的帮助!你知道吗
编辑
with open (filename) as filesearch:
filesearch = filesearch.readlines()
# ---------- Loop 1 for filename and filedate-----------------------------------
for line in filesearch:
if createdate in line: # extract "Create Time"
date = []
file = []
file.append(filename[42:])
#print(file)
date.append(line[15:]) # store all found filedates in array
#print(date)
list_logfile = list(zip(file,date))
#print(list_logfile)
# ---------- Loop 2 for finding string ------------------------------------------------------
for line in filesearch:
if tester in line: # extract "Sending Request: Tester"
data = []
message = []
start = '-> ' # take string from
end = ':\ ' # ens string at
number = line[line.find(start) + 3: line.find(end)] # [ord('-> '):ord(' :\ ')]
data.append(number) # store all found tester in a array
text = line[line.find(end) + 3:]
message.append(text) # store all found comments in a array
print(data)
down here i want to append the first file filename1 to the frist loop of strings ,
then append filename2 with the next loop of strings,
then the next and next...
目前没有回答
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