擅长:python、mysql、java
<p>您只需从<code>print</code>中的列表中解压(使用<code>*</code>)每个元组:</p>
<pre><code>a = [('AGR', 'Anggora'), ('PRS', 'Persia'), ('MNC', 'Main Coon')]
for tup in a:
print(*tup)
</code></pre>
<p>结果:</p>
<pre><code>AGR Anggora
PRS Persia
MNC Main Coon
</code></pre>