有没有办法把字符串以外的变量从asciimatics库传递到print\u at?你知道吗
手册说明:
print_at(text, x, y, colour=7, attr=0, bg=0, transparent=False)
使用指定的颜色和属性在指定位置打印文本。
参数
我正在测试的代码:
from asciimatics.screen import Screen
def print_test(screen):
var1 = "string" #works
var2 = int(2) #error
var3 = 3 #error
var4 = [1,2,3] #error
var5 = (1,2,3) #error
screen.print_at(var1, 10, 10, 1, 1)
screen.refresh()
input()
Screen.wrapper(print_test)
完整代码: 程序创建以绿色“@”表示的起点,然后进行10次移动,以黄色“@”表示。我想实现的是将黄色“@”改为数字,以查看按哪个顺序进行步骤。你知道吗
from asciimatics.screen import Screen
import os
import random
os.system('mode con: cols=51')
def exit_point():
global exitX
global exitY
wall = random.randint(1,4)
if wall == 1:
exitX = random.randint(1,49)
exitY = 0
elif wall == 2:
exitX = 49
exitY = random.randint(1,49)
elif wall == 3:
exitX = random.randint(1,49)
exitY = 49
elif wall == 4:
exitX = 0
exitY = random.randint(1,49)
def start_point():
global startX
global startY
startX = random.randint(2,48)
startY = random.randint(2,48)
def setup(screen):
screen.fill_polygon([[(0, 0), (50, 0), (50, 50), (0, 50)],[(1, 1), (49, 1), (49, 49), (1, 49)]])
exit_point()
screen.print_at("#", exitX, exitY, 1, 1)
start_point()
screen.print_at("@", startX, startY, 2, 1)
screen.refresh()
input()
def move(screen):
#trace list
trace = []
#bring back setup screen, waste of code but more intuiative
screen.fill_polygon([[(0, 0), (50, 0), (50, 50), (0, 50)],[(1, 1), (49, 1), (49, 49), (1, 49)]])
screen.print_at("#", exitX, exitY, 1, 1)
screen.print_at("@", startX, startY, 2, 1)
#Add starting point to the list
point = [startX,startY]
trace.append(point)
#1st move
moveX = startX + random.randint(-1,1)
moveY = startY + random.randint(-1,1)
point = [moveX,moveY]
trace.append(point)
screen.print_at("@", moveX, moveY , 3, 1)
#more moves
moves = 1
while moves < 10:
moveX = moveX + random.randint(-1,1)
moveY = moveY + random.randint(-1,1)
point = [moveX,moveY]
if point not in trace:
trace.append(point)
screen.print_at("@", moveX, moveY , 3, 1)
moves = moves + 1
screen.refresh()
input()
Screen.wrapper(setup)
Screen.wrapper(move)
input()
看来你的确切问题的答案是“不,你不能”。 然而,这并不意味着你不能实现你描述的目标。 作为参数传递时,为什么不将
print_at
要打印的数字转换成字符串呢?你知道吗在你的大代码里是这样的
看起来
print_at
只接受字符序列。但是您可以在将值传递给函数之前将其转换为字符串。你知道吗如果您想“好的,但是将我的所有
print_at
调用更改为使用str()
会很不方便”,那么您可以创建一个Screen
的子类来自动执行。你知道吗相关问题 更多 >
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