如果用户输入不在范围内，如何使用while循环？

Question

这是一个我很难完成的家庭作业。问题是：

Implement a function dartGame() that requests the user to enter x and y coordinates (each between -10 & 10) of a dart and computes whether the dart has hit the dartboard, a circle with center(0,0) and radius 8. If so, a string ‘It is in! :-)’ is printed, else ‘It isn’t in. :-(’ is printed. Note that the equation for a circle is x2 + y2 = r2; to make certain that the dart hits the board, the formula is x2 + y2 <= 82

>>> dartGame()
Enter x: 4
Enter y: 2.5
It is in! :-)
>>> dartGame()
Enter x: 9.9
Enter y: -9.9
It isn't in. :-(
>>>

这是我尝试的代码。我要做的是请求用户输入x。如果x < -10 or x > 10，我希望函数一直请求输入，直到满足参数。一旦建立了x坐标，我想对y做完全相同的事情。我的第一个while循环会无限重复，如果我猜一个超出范围的数字。例如，如果我猜-13它会重复，但是如果我猜4.5它仍然会重复。你知道吗

def dartGame():
    x = float(input("Enter  x: ", ))
    while x < -10 or x > 10:
            float(input("Out of range. Please select a number between -10 and 10: ", ))        
    y = float(input("Enter y: ", ))
    while y < -10 or y > 10:
            float(input("Out of range. Please select a number between -10 and 10: ", ))
    dartboard = x**2 + y**2
    if dartboard <= 8**2:
        print("It is in!")
    else:
        print("It isn't in. :-(")

Answer 1

应该在while循环中为x和y赋值

def dartGame():
    x = float(input("Enter  x: ", ))
    while x < -10 or x > 10:
            x = float(input("Out of range. Please select a number between -10 and 10: ", ))        
    y = float(input("Enter y: ", ))
    while y < -10 or y > 10:
            y = float(input("Out of range. Please select a number between -10 and 10: ", ))
    dartboard = x**2 + y**2
    if dartboard <= 8**2:
        print("It is in!")
    else:
        print("It isn't in. :-(")