从Java代码转换的Python错误

2024-10-01 22:30:02 发布

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我在学Python。所以,我有下面的Java代码来打印输入的数字的因子列表。我尝试在python中实现相同的逻辑。但是有一些错误。java代码如下:

public final class PrintFactors {

private PrintFactors() {}

public static void printFactors(int number) {
    if (number <= 0) throw new IllegalArgumentException("The number should be greater than 0.");
    printFactorsList(number, number + "*" + 1 + "\n", number);
}

private static void printFactorsList(int dividend, String factorString, int prevDivisor) {

    for (int divisor = dividend - 1; divisor >= 2; divisor--) {

        if (dividend % divisor != 0)
            continue;

        if (divisor > prevDivisor)
            continue;

        int quotient = dividend / divisor;


        if (quotient <= divisor) {
            if (quotient <= prevDivisor) {
                System.out.println(factorString + divisor + "*" + quotient);
            }
        }
        printFactorsList(quotient, factorString + divisor + "*", divisor);
    }
}

public static void main(String[] args) {
    printFactors(12);
    System.out.println();
    printFactors(32);
}

}

以上代码输出结果如下:

 $ java -cp . PrintFactors 32

32*1个

16*2个

8*4个

8*2*2个

4*4*2个

4*2*2*2

2*2*2*2*2

我的python代码如下:

def print_factors_list(dividend, factorstring, predivisor):

divisor = dividend - 1
for i in range(int(divisor), 2, -1 ):
    if dividend % i != 0:
        continue

    if divisor > predivisor:
        continue

    quotient = dividend / divisor


    if quotient <= divisor:
        if quotient <= predivisor:
            print factorstring + str(divisor) + "*" + str(quotient)


print_factors_list(quotient, str(factorstring) + str(divisor) + "*", divisor)


def print_factors(x):
if (x < 0):
    print "Enter a positive interger"
else:
    print_factors_list(x, str(x) + "*" + str(1) + "\n", x )

num = int(input("Enter a number: "))
print_factors(num)

我得到以下错误:

undefined: Error: local variable 'quotient' referenced before assignment

有人能帮我一下吗?我哪里做错了。当我将这些步骤实现为Java代码时,是否存在逻辑错误?谢谢。你知道吗


Tags: 代码numberif错误staticpublicdivisordividend

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