我知道可以在Python中调用模块本身,但也可以在模块本身中取消它吗?此代码应该只显示一次找到的名称。它继续打印,直到我用中断程序并从空闲状态获取KeyboardInterrupt
。你能帮我换些什么吗?附言:我有python3.4.2
from array import *
s = ["Turner", "Philips", "Stevenson", "Jones", "Gonzalez",
"Whitaker", "Bruner", "Webster", "Foster", "Anderson",
"Klein", "Connors", "Rivers", "Wilson", "Duncan"]
g = [94, 82, 87, 78, 65,
90, 85, 97, 70, 100,
57, 88, 73, 92, 84]
s.sort()
for i in range(15):
idx = int(i)
studentList = s[idx]
gradeList = g[idx]
print(studentList, gradeList)
print("")
print("Student five: ", s[4], g[4])
print("Student ten: ", s[9], g[9])
print("Student fifteen: ", s[14], g[14])
gradeAverage = (g[0] + g[1] + g[2] + g[3] + g[4] + g[5] + g[6] + g[7] + g[8]
+ g[9] + g[10] + g[11] + g[12] + g[13] + g[14]) / 15
print("")
print("The average of the list of the grades is: ", gradeAverage)
print("The median of the list of grades is: ", g[7])
print("")
def byRank():
studentFound = False
index = 0
searchValue = input("Student to be found: ")
while(studentFound == False) & (index <= len(s) - 1):
if s[index] == searchValue:
studentFound == True
print("Name", searchValue, "was found at index", index)
else:
index = index + 1
print("Name not found. Searching...")
print("Name is not in the array.")
byRank()
studentFound == True
不会更改studentFound
的值。使用单个=
进行赋值。或者用break
来处理这样一个简单的例子。你知道吗在Python中,通常不使用
while
循环来迭代序列—相反,如果不想使用内置的index
方法,这样的方法会更好:但一次只能解决一个问题。你知道吗
实现
byRank()
函数的正确方法是使用专门为此目的而设计的list.index()
方法。请尝试以下操作:代码中有几个错误。最大的错误是while循环测试。以下是修复方法
仅供参考汤姆亨特的答案是更好的方式来编写代码,如果你愿意放弃你的工作。你知道吗
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