擅长:python、mysql、java
<p>您可以这样使用<em>映射</em>函数:</p>
<pre><code>year = "07"
filenames = ['gdas1.janYEAR.w1', 'gdas1.janYEAR.w2','gdas1.janYEAR.w3']
filenames_yeared = map(lambda x: x.replace("YEAR", year), filenames)
</code></pre>
<p>您将得到:</p>
<pre><code>['gdas1.jan07.w1', 'gdas1.jan07.w2','gdas1.jan07.w3']
</code></pre>
<p>这就是你要找的吗?你知道吗</p>