我在Any servers with open tcp ports known?问 关于打开网站上的tcp端口,并被告知stackoverflow本身有tcp端口80打开。我执行了我的程序,它有点行为不端。你知道吗
import optparse
from socket import *
from threading import *
screenLock = Semaphore(value=1)
def connScan(tgtHost, tgtPort):
try:
connSkt = Socket(AF_INET, SOCK_STREAM)
connSkt.connect((tgtHost, tgtPort))
connSkt.send('ExploitMessage\r\n')
results = connSkt.recv(100)
screenLock.acquire()
print('[+]%d/tcpopen'%tgtPort)
print('[+] ' + str(results))
connSkt.close()
except:
screenLock.acquire()
print('[-]%d/tcp closed'%tgtPort)
finally:
screenLock.release()
def portScan(tgtHost, tgtPorts):
try:
tgtIP = gethostbyname(tgtHost)
except:
print("[-] Cannot resolve '%s': Unknown host"%tgtHost)
return
try:
tgtName = gethostbyaddr(tgtIP)
print("\n[+] Scan results for: " + tgtName[0] + ' , ' + tgtIP)
except:
print("\n[+] Scan results for " + tgtIP)
setdefaulttimeout(1)
for tgtPort in tgtPorts:
t = Thread(target=connScan, args=(tgtHost, int(tgtPort)))
t.start()
def main():
parser = optparse.OptionParser('usage%prog ' + ' -H <target host> -p <target port>')
parser.add_option('-H', dest='tgtHost', type='string', help='specify target Host')
parser.add_option('-p', dest='tgtPort', type='string', help='specify target port[s] separated by comma')
(options, args) = parser.parse_args()
tgtHost = options.tgtHost
tgtPorts = str(options.tgtPort).split(',')
if ((tgtHost == None) | (tgtPorts[0]==None)):
print(parser.usage)
exit(0)
portScan(tgtHost, tgtPorts)
if __name__ == "__main__":
main()
这是我的全部密码。它确实给了我stackoverflow的“真实”名称,但是说tcp端口将被关闭。我做错什么了?我尝试过其他网站,应该有一个特定的港口开放,但它总是声称港口将关闭。你知道吗
这是命令shell中的输出:
[+] Scan results for: li547-15.members.linode.com , 198.74.50.15
[-]80/tcp closed
请告诉我为什么不行。你知道吗
目前没有回答
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