擅长:python、mysql、java
<p>也可以使用<code>collections.Counter</code>:</p>
<pre><code>from collections import Counter
LLList = [ ["A", "B", 30], ["C", "B", 30], ["D", "B", 20], ["D", "L", 60] ]
a = Counter([i[2] for i in LLList if i[1]=="B"])
print (a.most_common(2))
#[(30, 2), (20, 1)]
print (sorted(a.items(),key=lambda x: x[0],reverse=True)) #or get highest value
#[(30, 2), (20, 1)]
</code></pre>