通过函数参数访问Pythons预定义的数组名称

Question

我在代码中填充了数组，我想通过在函数参数中调用它的名称来访问它。 我不是很准确，我需要访问数组名称、和值。我只是把整个代码粘贴到你身上，也许我遗漏了什么：

#the path of the dictionary txt files
dictionarypath = 'C:\\src\\'
#example files: qone.txt, adj.txt, subj.txt, gly.txt


#fill "dictionary-file-named" arrays to the words
dictnum=0
dictionaryfiles = []
for r, d, f in os.walk(dictionarypath):
    for file in f:
        if '.txt' in file:   
            dictname=(file[0:-4])
            dictionaryfiles.append(dictname)

            #getting the word from the files and put them into the named arrays (ex.: from subject.txt to subj[])
            dictfile = dictionarypath + dictionaryfiles[dictnum] + '.txt'

            with codecs.open(dictfile, encoding='latin1') as fp:

                line = fp.readline()
                vars()[dictname]=[] #set the actual array to empty first
                while line:
                    vars()[dictname].append(line.strip())
                    line = fp.readline()
            dictnum=dictnum+1   

#this generate the random sentence
def rstc(*pos): 
        for x in range(len(pos)):            
            actdictname=(pos[x])
            if len(actdictname) > 0:
                gennum=random.randrange(0, len(actdictname), 1)                
                sys.stdout.write(actdictname[gennum]+" ")

#qone -> question word (what)
#adj  -> adjectives
#subj -> subjects
#gly  -> glyps (!,.)

rstc(qone,adj,subj,subj,gly)

Answer 1

另一种思考是：

cars = ["Ford", "Volvo", "BMW"]
sports= ["Football", "Basketball", "Judo"]

def myFunc(what):
    print(eval(what[0])[0])# ->> prints out "Ford"
    print(eval(what[1])[1])# ->> prints out "Basketball"

myFunc(["cars", "sports"])

或者

def myFunc(what):
    print(what[0][0])# ->> prints out "Ford"
    print(what[1][1])# ->> prints out "Basketball"

myFunc(cars, sports)

Answer 2

您可以将两个数组作为单独的参数传入，并在函数中使用它们：

def myFunc(cars, sports):
    print(cars[0]) # ->> prints out "Ford"
    print(sports[1]) # ->> prints out Basketball

myFunc(cars, sports)

如果必须将它们分组为单个函数参数，可以这样做：

def myFunc(stacked_list):
   print(stacked_list[0][0]) # ->> prints out "Ford"
   print(stacked_list[1][1]) # ->> prints out Basketball

myFunc([cars, sports])

Answer 3

用myFunc(cars, sports)调用函数应该可以正常工作。否则，代码似乎可以工作。你知道吗