为什么我的程序出错（python）？

Question

这段代码可以模拟合并2个联系人簿。你知道吗

我的代码错误在第18行没有明显的原因与短语错误。我很确定这句话是正确的，程序应该运行，但每次我得到一个短语错误。你知道吗

 class ContactBook:
        """
        This class represents a book of contacts.
        It can store names and phone numbers.
        """

        def __init__(self):
        # Create an empty dictionary
        self.contacts = {}

    def __repr__(self):
        # Just print a string version of the dictionary
        return str(self.contacts)
    def __add__(self, other):
        con2 = ContactBook()
        for name in self.contacts:
            if name in other.contacts and self.contacts[name] != other.contacts[name]:
                con2.contacts[name] = self.contacts[name] + " or " + other.contacts[name]
            else:
                con2.contacts[name] = self.contacts[name]
        for name in other.contacts:
            if name not in self.contacts:
                con2.contacts[name] = other.contacts[names]
        return con2

    def add_contact(self, name, number):
        # Adds a name --> phone number pair to
        # the dictionary.
        self.contacts[name] = number

#############################
# Program starts here

cb1 = ContactBook()
cb2 = ContactBook()

cb1.add_contact("Jonathan", "444-555-6666")
cb1.add_contact("Puneet", "333-555-7777")
cb2.add_contact("Jonathan", "222-555-8888")
cb2.add_contact("Lisa", "111-555-9999")



# The result of this should be a book that
# looks like this:
#
# {
#     "Jonathan": "444-555-6666 or 222-555-8888",
#     "Puneet": "333-555-7777",
#     "Lisa": "111-555-9999"
# }
cb3 = cb1 + cb2
print cb1
print cb2
print cb3

Answer 1

我认为names在这里是一个拼写错误：

con2.contacts[name] = other.contacts[names]