使用Google的findplacefromtext InvalidURL时出错

Question

我正在尝试使用googleapi的findplacefromtext获取地址的详细信息。我的代码是这样的：

def get_google_address(address):
    API_KEY = 'MY_API_KEY'
    URL = ('https://maps.googleapis.com/maps/api/place/findplacefromtext/json?input={add}&inputtype=textquery&fields=formatted_address,name,geometry&key={API_KEY}').format(add=address,API_KEY=API_KEY)
    print(URL)
    response = urllib.request.urlopen(URL)
    data = json.load(response)
    return (data)

如果按如下方式调用函数：get_google_address('1600 amphitheatre pkwy mountain view ca')，则会出现以下错误：

InvalidURL: URL can't contain control characters. '/maps/api/place/findplacefromtext/json?input=1600 amphitheatre pkwy mountain view ca&inputtype=textquery&fields=formatted_address,name,geometry&key=API_KEY' (found at least ' ')

但是，如果我将URL粘贴到浏览器中，它就会工作。请让我知道我错过了什么。URL如下：https://maps.googleapis.com/maps/api/place/findplacefromtext/json?input=1600 amphitheatre pkwy mountain view ca&inputtype=textquery&fields=formatted_address,name,geometry&key=API_KEY

Answer 1

根据@geocodezip的评论，需要对URL进行编码：

dict1 = {'input':address, 'key':API_KEY}
qstr = urllib.parse.urlencode(dict1) 
URL = 'https://maps.googleapis.com/maps/api/place/findplacefromtext/json?inputtype=textquery&fields=formatted_address,name,geometry&'
URL = URL + qstr
response = urllib.request.urlopen(URL)
data = json.load(response)
return (data)