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<p>我有一个包含大量字典的数组。但是,我希望对字典进行排序,使字典中的特定键具有最大值。
例如,我有一个如下的列表</p>
<pre><code>[
{
"num_gurus": 40,
"id": 119749,
"code": null,
"name": "ART 198P",
"short_name": "ART 198P",
"title": "Directed Group Study",
"department_long": null,
"full_name": "Directed Group Study",
"department_short": "ART"
},
{
"num_gurus": 3,
"id": 119825,
"code": null,
"name": "ASAMST 198P",
"short_name": "ASAMST 198P",
"title": "Supervised Group Study",
"department_long": null,
"full_name": "Supervised Group Study",
"department_short": "ASAMST"
},
{
"num_gurus": 200,
"id": 119904,
"code": null,
"name": "AST 636",
"short_name": "AST 636",
"title": "Baudelaire: Art Poetry Modernity",
"department_long": null,
"full_name": "Baudelaire: Art Poetry Modernity",
"department_short": "AST"
}
]
</code></pre>
<p>我希望我的输出对字典进行排序,其中键属性'num\u gurus'的值从最大到最小。预期产出将是。你知道吗</p>
<pre><code>[
{
"num_gurus": 200,
"id": 119904,
"code": null,
"name": "AST 636",
"short_name": "AST 636",
"title": "Baudelaire: Art Poetry Modernity",
"department_long": null,
"full_name": "Baudelaire: Art Poetry Modernity",
"department_short": "AST"
}
{
"num_gurus": 40,
"id": 119749,
"code": null,
"name": "ART 198P",
"short_name": "ART 198P",
"title": "Directed Group Study",
"department_long": null,
"full_name": "Directed Group Study",
"department_short": "ART"
},
{
"num_gurus": 3,
"id": 119825,
"code": null,
"name": "ASAMST 198P",
"short_name": "ASAMST 198P",
"title": "Supervised Group Study",
"department_long": null,
"full_name": "Supervised Group Study",
"department_short": "ASAMST"
}
]
</code></pre>
<p>我已经试过了</p>
<pre><code> for items in load_as_json:
for key, val in sorted(items['num_gurus'].iteritems(), key=lambda (k,v): (v,k), reverse=True):
print key,val
This throws me error and doesn't do what I actually want to.
This is the error I got.
File "utils.py", line 61, in GetPopularCoursesBasedOnGurus
for key, val in sorted(str(items['num_gurus']).iteritems(), key=lambda (k,v): (v,k)):
AttributeError: 'str' object has no attribute 'iteritems'
</code></pre>