我得到了以下代码,试图调整reportlab鸭嘴兽flowable文本的字体大小,直到它适合我给定的可用高度。但是我发现flowable段并没有在递归的每个循环中保存它的style.fontSize属性,python的baulks具有无限递归。
def fits_space(w,h,aW,aH,p):
"""
Determines if inputted text fits in the space given for a paragraph
and if it doesn't, reduces the font-size until it does.
"""
if w<=aW and h<=aH:
# return font size to apply it to the para again
print "final font_size: %d" % p.style.fontSize
return p # now render the paragraph in the doctemplate
else:
p.style.fontSize -= 1
w,h = p.wrap(aW, aH)
fits_space(w,h,aW,aH,p)
def renderPage(name, text):
doc = SimpleDocTemplate("%s.pdf" % name)
parts = []
style = ParagraphStyle(name='fancy')
style.fontSize = 150
p = Paragraph(text, style)
aW = PAGE_WIDTH-4*inch # available width and height
aH = PAGE_HEIGHT-4*inch
w,h = p.wrap(aW, aH) # find required space
p = fits_space(w,h,aW,aH,p) # recursively fit the font size to the text
parts.append(p)
doc.build(parts)
有人能告诉我为什么-在fits_space()函数中,在else子句中,当我调用p.wrap(aW,aH)时,输出的值与我将段落的字体大小减小1之前的值相同吗?如果我减小字体大小的话,包装的高度肯定要小一些?
你知道我错在哪里吗?
更新 Nitzie在下面的代码几乎可以工作只需要在样式中添加一个resizer。在我的例子中也是leading:
def shrink_font_size(aW, aH, text, style):
"""Shrinks font size by using pdfmetrics to calculate the height
of a paragraph, given the font name, size, and available width."""
def break_lines(text, aW):
# simpleSplit calculates how reportlab will break up the lines for
# display in a paragraph, by using width/fontsize.
return simpleSplit(text, style.fontName, style.fontSize, aW)
def line_wrap(lines, style):
# Get overall width of text by getting stringWidth of longest line
width = stringWidth(max(lines), style.fontName, style.fontSize)
# Paragraph height can be calculated via line spacing and number of lines.
height = style.leading * len(lines)
return width, height
lines = break_lines(text, aW)
width, height = line_wrap(lines, style)
while height > aH or width > aW:
style.fontSize -= 1
style.leading -= 1 # do this if you're leading is based on the fontSize
lines = break_lines(text, aW)
width, height = line_wrap(lines, style)
短暂性脑缺血发作
目前没有回答
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