想知道一个特定字符在一个特定句子中出现的次数吗

Question

代码

sentence = input("Please enter a sentence:")
character = input("Please enter a single character:")

counter = 0

1. 使用while循环：

while len(character) > 1:
      character = input("Please try again, enter a single character:")

1. 我的问题是if语句对我不起作用。你知道吗

while len(sentence) > counter:
    if sentence[0].__contains__(character):
        counter += 1
        print(counter)
    if sentence[1].__contains__(character):
        counter += 1
        print(counter)
    if sentence[3].__contains__(character):
        counter += 1
        print(counter)
    if sentence[4].__contains__(character):
        counter += 1
        print(counter)
    if sentence[5].__contains__(character):
        counter += 1
        print(counter)
    if sentence[6].__contains__(character):
        counter += 1
        print(counter)
    if sentence[7].__contains__(character):
        counter += 1
        print(counter)

主要的问题是，如果用户输入的句子大于或小于代码不使用的if语句的数量

Answer 1

如果没有导入，只需将句子中的字符替换为空字符串，然后比较两个句子的长度：

sentence = input("Please enter a sentence:")
character = input("Please enter a single character:")

counter = len(sentence) - len(sentence.replace(character, ''))

把它放在一个循环中：

sentence = input("Please enter a sentence:")
while 1:
    character = input("Please enter a single character:")
    print(len(sentence) - len(sentence.replace(character, '')))