涉及列表的格式问题

Question

我有一个函数，它接受一个名称作为输入，把它放入一个列表，然后对它运行ord（）。不过，我有一些（我相信）格式问题。 我想让它看起来像这样：

b = (ascii value)
a = (ascii value)
t = (ascii value)
m = (ascii value)
a = (ascii value)
n = (ascii value)

名称显示正确，但ascii值显示如下：

b = [98, 97, 116, 109, 97, 110]
a = [98, 97, 116, 109, 97, 110]
t = [98, 97, 116, 109, 97, 110]
m = [98, 97, 116, 109, 97, 110]
a = [98, 97, 116, 109, 97, 110]
n = [98, 97, 116, 109, 97, 110]

我不知道哪里出错了，下面是我为它编写的代码：

def x():
     name = requestString("name")
     usersName = list(name)
     ascii = [orc(c) for c in usersName]
     for name in name: 
          print name, "=", ascii 

谢谢！你知道吗

编辑： 谢谢，非常感谢。去我错的地方！你知道吗

Answer 1

下面是对你的错误之处的一点回顾：

def x():
     name = requestString("name")
     usersName = list(name)
     ascii = [orc(c) for c in usersName] # here's the list
     for name in name: 
          print name, "=", ascii # and you're printing it here everytime

你可以像这样做：

def x():
     name = requestString("name")
     # usersName = list(name) # no need for this line, you can iterate over the string
     ascii = [orc(c) for c in name] #so this is just name
     for i, c in enumerate(name):  # use c for your character var name, 
          print c, "=", ascii[i]   # and enumerate provides the index

由于您不返回任何内容，因此创建列表是不必要的，您还可以动态提供ord（c）：

def print_ords_of_word(name):
    for c in name:
        print c, '=', ord(c)

Answer 2

您可以在单个循环中进行：

for item in name:
    print item, "=", ord(item)

演示：

>>> def x(name):
...      for item in name:
...           print item, "=", ord(item)
... 
>>> x('batman')
b = 98
a = 97
t = 116
m = 109
a = 97
n = 110

Answer 3

ascii是所有字符的ord列表。要将它们与它们所代表的字符配对，请使用^{}：

for num, char in zip(ascii, name):
    print "'{0}'={1}".format(char, num)