无法中断while循环，该循环正在搜索列出的值

Question

所以我很肯定我做错了，但我不知道怎么做。我本来打算用一个数组，但不知道怎么用。我对Python不那么毛茸茸的一面还很陌生（在学校学习） 如果我能帮上忙，我会非常感激的。你知道吗

所以我试着练习设计和编程，我想用这样的图表来比较一下神奇宝贝的类型：

http://i.kinja-img.com/gawker-media/image/upload/s--6gT1hiPW--/fxovveduxtomv4srnqk1.png

所以，我的想法是输入类型，然后输出它的优点和缺点。但就我的一生而言，我无法通过选择一种类型的初始阶段。你知道吗

以下是我的前几句台词：

Elements = "Normal","Fire","Water","Grass","Electric","Bug","Flying","Ground","Rock","Posion","Dragon","Dark","Fairy","Psychic","Steel","Fighting","Ice"
type1 = input("Please input a type")
while type1 != Elements:
    type1 = input("Please input a real type")

print("Good Job, this part works!") # But it doesn't get to this point...

我很抱歉这太糟糕了，但每个人一开始都很天真，对吧？ 提前谢谢你能给我的任何帮助！你知道吗

Answer 1

我想你应该检查type1是否在元素中，而不是是否等于它。元素是一个字符串元组，类型1将只是一个字符串。这两样东西永远不会相等。你知道吗

您可以使用in关键字测试它是否在中，如下所示：

while( type1 not in Elements ):
    type1 = raw_input( "Enter a valid type" )

Answer 2

首先，您需要一个列表来存储所有类型，然后反复请求用户输入，然后将输入与预定义的元素列表进行匹配，如果找到匹配项，则中断while循环，否则继续，这就是本例中要遵循的简单算法。你知道吗

elements = ["Normal","Fire","Water","Grass","Electric","Bug","Flying","Ground","Rock","Posion","Dragon","Dark","Fairy","Psychic","Steel","Fighting","Ice"]
#Initialized the various types in a list.
while True:    #Infinite loop
    type1 = input("Please input a real type")   #Taking input from the user
    if type1 in elements:    #Checking if the input is already present in the given list of elements.
        print("Good Job, this part works!")
        break

Answer 3

你想看看一个词是否等于一个列表，这永远不会是真的，你想看看这个词是否在列表中

elements = "Normal","Fire","Water","Grass","Electric","Bug","Flying","Ground","Rock","Posion","Dragon","Dark","Fairy","Psychic","Steel","Fighting","Ice"
type1 = input("Please input a type")
while type1 not in elements:
    type1 = input("Please input a real type")

print("Good Job, this part works!") # But it doesn't get to this point...