擅长:python、mysql、java
<p>你可以做:</p>
<pre><code>def myfunc(num):
a=str(num)
for i in range(len(a)):
l1=a[:i]
l2=a[i:]
if l1 in l2:
b=l1
return [int(b), int(a[len(b):])]
</code></pre>
<p>这将给你:</p>
<pre><code>>>> myfunc(845538455314391440)
[84553, 8455314391440]
</code></pre>