在python中从列表中随机选择两个组

Question

我该如何编写代码，让9个人的列表尽可能平均地分成两辆车，但在python中他们被随机地放在每辆车中？ 基本上我在寻找类似的回报：
车1:Person8、Person2、Person4、Person7
车2:Person5，Person1，Person3，Person6，Person9

Answer 1

把整张单子洗一下，然后把单子分成两张，一张有4个人，另一张有剩下的人：

import random

people = ['foo', 'bar', 'baz', 'eggs', 'ham', 'spam', 'eric', 'john', 'terry']
random.shuffle(people)
car1, car2 = people[:4], people[4:]

如果无法直接对人员列表排序，请改用random.sample()：

people = ['foo', 'bar', 'baz', 'eggs', 'ham', 'spam', 'eric', 'john', 'terry']
shuffled = random.sample(people, len(people))
car1, car2 = shuffled[:4], shuffled[4:]

后一种方法的演示：

>>> import random
>>> people = ['foo', 'bar', 'baz', 'eggs', 'ham', 'spam', 'eric', 'john', 'terry']
>>> shuffled = random.sample(people, len(people))
>>> shuffled[:4], shuffled[4:]
(['bar', 'baz', 'terry', 'ham'], ['spam', 'eric', 'foo', 'john', 'eggs'])

Answer 2

from random import shuffle
x = [i for i in range(10)]
shuffle(x)
print x
mid = int(len(x)/2)
car1 = x[:mid]
car2 = x[mid:]
print car1
print car2