如何在python代码中向后发送提示？

Question

我用randomint函数编写了一个简单的数字猜测游戏。你知道吗

假设是我写的，看起来有点像这样：

 import blah
 import blah

 print ("Hello, and welcome to the guesser")

 Answer1 = (randomint(1,5))
 Guess1 = int(input("Input a number 1-5")

 if Guess1 == Answer1:
      print ("You got lucky that time")

 elif Guess1 < 6 and != Answer1:
      #send back to guess again

 elif Guess1 > 5:
      print ("Invalid Number")
      #send back to guess again

这可能是一个非常愚蠢的问题和初学者的东西，但是，有没有一个功能，可以满足我的需要和希望，送人回来猜一次数字？你知道吗

Answer 1

您正在搜索的内容称为编程中的循环。你知道吗

你可以这样做：

import random

Answer1 = random.randint(1,5)

while True:
    Guess1 = int(input("Input a number 1-5 >>"))

    if Guess1 == Answer1:
        print ("You got luck this time")
        break

    elif Guess1 < 6 and Guess1 != Answer1:
        #send back to guess again
        print ("Try again!")
        continue

    elif Guess1 > 5:
        print ("Invalid Number")
        #send back to guess again
        continue