我是Python新手,正在尝试从json响应创建一个新的结构。这两个json响应是来自两个环境的测试,但长度和顺序相同,只是结果不同,为简洁起见,我简化了我的示例。你知道吗
响应1.json
[{"qa":"o"}, {"qa":"o"}]
响应2.json
[{"prod":"x"}, {"prod": "x"}]
创建.py
with open('response1.json') as data_file:
data1 = json.load(data_file)
with open('response2.json') as data_file:
data2 = json.load(data_file)
#i want to be able to create a structure like this:
# [{"qa":"o", "prod":"x"},{"qa":"o", "prod":"x"}]
list = []
#This is wrong but was thinking that logic would be close to this.
for i in range(0,len(data1)):
list[i]['qa'] = data1[i]['qa']
for i in range(0,len(data2)):
list[i]['prod'] = data[i]['prod']
1)Python 3.5使用
zip()
函数和字典解包运算符**
的解决方案:输出:
2)Python<;3.5使用
dict.update()
方法的解决方案:结果:
这里有一个更优雅但可能效率更低的解决方案:
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