列出任何项目

Question

所以我写了一个井字游戏，我用这个作为列表的格式：

board = [["0", "1", "2"],
         ["3", "4", "5"],
         ["6", "7", "8"]]

所以当我为tic-tac-toe写人工智能的时候，我遇到了一个问题

for i in board:
    if i == ["X","X"," "]:
        return i[2]
    elif i == ["X"," ","X"]:
        return i[1]
    elif i == [" ","X","X"]:
        return i[0]
for i in horzboard:
    if i == ["X","X"," "]:
        return i[2]
    elif i == ["X"," ","X"]:
        return i[1]
    elif i == [" ","X","X"]:
        return i[0]

它不能工作，因为python在这个项目上是特定的，所以有没有一种方法可以告诉python这就是我想要的（例如*s是任何东西）：

for i in board:
    if i == ["X","X",*]:
        return i[2]
    elif i == ["X",*,"X"]:
        return i[1]
    elif i == [*,"X","X"]:
        return i[0]
for i in horzboard:
    if i == ["X","X",*]:
        return i[2]
    elif i == ["X",*,"X"]:
        return i[1]
    elif i == [*,"X","X"]:
        return i[0]

谢谢！你知道吗

Answer 1

如果您试图在一个电路板中找到不是“X”的值（这是您的示例代码所建议的），那么我将使用一个函数，您可以根据您的示例将board或horzboard传递给它。你知道吗

# This will return a list of all non-X values in the entire board

def return_marks(board):

    mark_list = [(arr,mark) for arr in board for mark in arr if mark != 'X']

        return mark_list

# If you just want the first non-X value to cause the function to stop and return that non-X value, then try this.

def return_marks(board):    
    for row in board:

        for mark in row:

            if mark != 'X':
                return mark