擅长:python、mysql、java
<p>您可以使用<code>itertools.count</code>:</p>
<pre><code>from itertools import count
i = count()
print([[next(i) for _ in range(len(l))] if isinstance(l, list) else next(i) for l in ListNo])
</code></pre>
<p>这将输出:</p>
<pre><code>[[0, 1, 2], [3, 4], 5, 6, [7, 8, 9]]
</code></pre>