python如何解析指定div标记中的标记

Question

我已经尝试过这个网站上的其他解决方案，但仍然无法解决问题，我的问题是：

<div class="ds"><div title="Today" class="dh">...<div title="Pazartesi" class="dh">26 Agu Pzt

我想解析这个“ds”类中的所有div标题，谢谢你的帮助

Answer 1

使用BeautifulSoup、lxml或类似模块代替regex。你知道吗

---

BeautifulSoup：

from bs4 import BeautifulSoup

text = '<div class="ds"><div title="Today" class="dh">...<div title="Pazartesi" class="dh">26 Agu Pzt'

soup = BeautifulSoup(text, 'html.parser')

for item in soup.select('.ds div[title]'):
    print(item['title'])

# or as list comprehensions    

titles = [item['title'] for item in soup.select('.ds div[title]')]
print(titles)

---

lxml：

import lxml.html

text = '<div class="ds"><div title="Today" class="dh">...<div title="Pazartesi" class="dh">26 Agu Pzt'

soup = lxml.html.fromstring(text)

for item in soup.cssselect('.ds div[title]'):
    print(item.attrib['title'])

# or as list comprehensions    

titles = [item.attrib['title'] for item in soup.cssselect('.ds div[title]')]
print(titles)

---

PyQuery：

import pyquery

text = '<div class="ds"><div title="Today" class="dh">...<div title="Pazartesi" class="dh">26 Agu Pzt'

soup = pyquery.PyQuery(text)

for item in soup('.ds div[title]'):
    print(item.attrib['title'])

# or as list comprehensions    

titles = [item.attrib['title'] for item in soup('.ds div[title]')]
print(titles)

---

parsel：（由Scrapy's Selectors使用）

import parsel

sel = parsel.Selector(text)

for item in sel.css('.ds div[title]'):
    print(item.attrib['title'])

titles = [item.attrib['title'] for item in sel.css('.ds div[title]')]
print(titles)