如何使用python在hangman中两次获得相同的单词

Question

这是我的代码，我认为所有的东西都能工作，除了它不需要任何超过一个的值。请帮帮我。你知道吗

word = input("What's your word?\n").upper() forguess = " ".join(word) char = "_" for index in range(len(word)): word = word[:index] + char + word[index+1:] spacedwords = " ".join(word) print(spacedwords) chances = 5 while chances != 0: print("You have " + str(chances) + " chances left\n") letter = input("Guess the letters: \n").upper() if letter in forguess: #check if the input letter is in original word pos = forguess.index(letter) #gets the letter position from forguess original word spacedwords = spacedwords[:pos] + letter + spacedwords[pos+1:] #replace word in the blank ones print(spacedwords) if spacedwords == forguess: print("YOU WON!!!") break else: chances -= 1 if chances == 0: print("YOU LOOSE!!!")

Answer 1

代码不起作用的主要原因是，虽然猜字母时spacedwords会改变，但forguess不会。这样，您的index调用总是只找到第一个出现的letter。尽可能少地修改代码（有更有效的方法），下面是一个如何实现所需的示例：

word = input("What's your word?\n").upper()
forguess = " ".join(word)
char = "_"
for index in range(len(word)):
    word = word[:index] + char + word[index+1:]
spacedwords = " ".join(word)
print(spacedwords)

chances = 5

while chances != 0:
    print("You have " + str(chances) + " chances left\n")
    letter = input("Guess the letters: \n").upper()
    if letter in forguess:              #check if the input letter is in original word
        positions = [i for i,x in enumerate(forguess) if x == letter]    #gets all letter positions from forguess original word
        for pos in positions:
            spacedwords = spacedwords[:pos] + letter + spacedwords[pos+1:]  #replace all blank positions with letter
        print(spacedwords)
        if spacedwords == forguess:
            print("YOU WON!!!")
            break
    else:
        chances -= 1
        if chances == 0:
            print("YOU LOOSE!!!")

编辑：

我第一次误解了OP的意图，这里又是一个试图尽可能少地修改原始代码的示例。我引入了一个新变量original，它在开头与forguess相同。现在，每次正确猜测一个字母时，forguess都会被修改（猜测的字母会变成NULL字符），这样在下一次搜索中它就不会再出现了。最后，将spaceedwords与original而不是forguess进行比较。你知道吗

word = input("What's your word?\n").upper()
forguess = " ".join(word)
original = " ".join(word)
char = "_"
for index in range(len(word)):
    word = word[:index] + char + word[index+1:]
spacedwords = " ".join(word)
print(spacedwords)

chances = 5

while chances != 0:
    print("You have " + str(chances) + " chances left\n")
    letter = input("Guess the letters: \n").upper()
    if letter in forguess:              #check if the input letter is in original word
        pos = forguess.index(letter)   #gets the letter position from forguess original word
        spacedwords = spacedwords[:pos] + letter + spacedwords[pos+1:]  #replace word in the blank ones
        forguess = forguess[:pos] + chr(0) + forguess[pos+1:]

        print(spacedwords)
        if spacedwords == original:
            print("YOU WON!!!")
            break
    else:
        chances -= 1
        if chances == 0:
            print("YOU LOOSE!!!")

注意：

如果将forguess转换为单个字符的列表，整个问题将更容易处理。你知道吗