擅长:python、mysql、java
<p>可以使用集合直接查找交点</p>
<pre><code>a = [["abc", "def", "ghd"], ["1", "2", "3"]]
b = [["abc", "olnaf", "kjbdsa"], []]
c = [["abc", "aeufga", "älaga"], ["1", "2"]]
for i, (a, b, c) in enumerate(zip(a, b, c)):
print("Index", i)
print(" a & b:", set(a) & set(b))
print(" b & c:", set(b) & set(c))
print(" a & c:", set(a) & set(c))
</code></pre>
<p>输出</p>
<pre><code>Index 0
a & b: {'abc'}
b & c: {'abc'}
a & c: {'abc'}
Index 1
a & b: set()
b & c: set()
a & c: {'2', '1'}
</code></pre>