下面是我想要分割并存储在变量中的文本。你知道吗
Pppp CCCC TTTT MMMMM SSSSSS Oono.
1 NIL fL-E 10UU (SPD+), 1000XXXXX (SPD) WEEEEEEEEEEEEE CATTTTTTTTT
44 10/100/1000BBBBB Ppppppp OOo E SSSSSS WS-XXXXX-RRRRR+I CATTTTTTTTT
44 10/100/1000BBBBB Ppppppp OOo E SSSSSS WS-XXXXX-RRRRR+I CATTTTTTTTT
44 10/100/1000BBBBB Ppppppp OOo E SSSSSS WS-XXXXX-RRRRR+I CATTTTTTTTT
44 10/100/1000BBBBB Ppppppp OOo E SSSSSS WS-XXXXX-RRRRR+I CATTTTTTTTT
44 10/100/1000BBBBB Ppppppp OOo E SSSSSS WS-XXXXX-RRRRR+I CATTTTTTTTT
我想把它分开 变量1:-
Pppp
1
44
44
44
44
44
变量2:-
CCCC TTTT
NIL fL-E 10UU (SPD+), 1000XXXXX (SPD)
10/100/1000BBBBB Ppppppp OOo E SSSSSS
10/100/1000BBBBB Ppppppp OOo E SSSSSS
10/100/1000BBBBB Ppppppp OOo E SSSSSS
10/100/1000BBBBB Ppppppp OOo E SSSSSS
10/100/1000BBBBB Ppppppp OOo E SSSSSS
变量3:-
MMMMM
WEEEEEEEEEEEEE
WS-XXXXX-RRRRR+I
WS-XXXXX-RRRRR+I
WS-XXXXX-RRRRR+I
WS-XXXXX-RRRRR+I
WS-XXXXX-RRRRR+I
变量4:-
SSSSSS Oono.
CATTTTTTTTT
CATTTTTTTTT
CATTTTTTTTT
CATTTTTTTTT
CATTTTTTTTT
CATTTTTTTTT
每个变量都应该存储指定的值
我有密码试过:-你知道吗
with open ('sh_module.txt', 'r') as module_info:
lines = module_info.read().splitlines()[6:]
for l in lines:
if not l.isspace():
storeSplit = (" ".join(l.split()[1:10]))
A_of_splitOfstoreSplit , B_of_splitOfstoreSplit = storeSplit.split('W')
print (storeSplit)
代码不起作用。:-(
你知道吗注:-该这样写的文本与文本文件中的文本一样。一定要考虑空间。!你知道吗
谢谢你的帮助。!:-)
编辑:回答后找到How to efficiently parse fixed width files?。这个答案是针对您的问题的,dupe展示了使用structs等处理定长文件解析的其他方法
您似乎有一个固定宽度的格式—您可以简单地将每一行拆分为一个列表,然后使用zip将其转换为列。你知道吗
创建文件:
处理文件:
输出:
您可以通过
variabs["Pppp"]
、variabs["SSSSSS Oono."]
等访问这些列还有其他方法可以处理这个问题,更多信息请参见How to efficiently parse fixed width files?
编辑:使用枚举:
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