在python中按奇偶升序排序列表

Question

我有一个列表listOfNumbers = [3,2,1,4,5,6,7,8,9,22,25,16,17,28]我想按升序排列这个列表，但首先是奇数，然后是偶数，如下所示：

[1, 5, 7, 9, 11, 15, 19, 29,'startOF->evens', 4, 8, 10, 14, 16, 28, 32, 66]

不带排序功能

我试过了，但是我错了

data_list = [3,2,1,4,5,6,7,8,9,22,25,16,17,28]
new_list = []
while data_list:
    minimum = data_list[0]
    for x in data_list: 
        if x < minimum:
            minimum = x
    new_list.append(minimum)
    data_list.remove(minimum)
    print (new_list)
def Huhu(data_list):
  ev_li = ''
    od_li = ''
    for i in data_list: 
        if (i % 2 == 0): 
            ev_li.append(i) 
        else: 
            od_li.append(i)
    print(new_list,od_li "startOF->evens",ev_li) 

谢谢你的回复

data_list = [3,2,1,4,5,6,7,8,9,22,25,16,17,28]
new_list = []

while data_list:
    minimum = data_list[0]  # arbitrary number in list 
    for x in data_list: 
        if x < minimum:
            minimum = x
    new_list.append(minimum)
    data_list.remove(minimum)
odds = []
evens = []
for i in new_list:
    if i % 2 == 0:
        evens.append(i)
    else:
        odds.append(i)
print(odds,"startOF->evens", evens)

Answer 1

您可以将sorted与自定义key参数一起使用来排序。你知道吗

>>> sorted(listOfNumbers, key=lambda i: (i%2==0, i))
[1, 3, 5, 7, 9, 17, 25, 2, 4, 6, 8, 16, 22, 28]

在这种情况下，可以先按奇数/偶数排序，然后按值本身排序。你知道吗

Answer 2

如果您想知道代码失败的原因：

data_list = [3,2,1,4,5,6,7,8,9,22,25,16,17,28]
new_list = []
while data_list:
    minimum = data_list[0]
    for x in data_list: 
        if x < minimum:
            minimum = x
    new_list.append(minimum)
    data_list.remove(minimum)
    print (new_list)
def Huhu(data_list):
    ev_li = list()
    od_li = list()
    for i in data_list: 
        if (i % 2 == 0): 
            ev_li.append(i) 
        else: 
            od_li.append(i)
    print(new_list,od_li, "startOF->evens",ev_li) 

您有三个错误：

第一：缩进问题：

def Huhu(data_list):
  ev_li = ''
    od_li = '' <- Here

第二：此处缺少逗号：

print(new_list,od_li [here] "startOF->evens",ev_li) 

第三：

ev\u li和od\u li必须是list

但可以肯定的是，@CoryKramer更干净：p