擅长:python、mysql、java
<p>在柜台上循环一个列表:</p>
<pre><code>[list(k) + [v] for k, v in res.iteritems()]
</code></pre>
<p>演示:</p>
<pre><code>>>> from collections import Counter
>>> res = Counter({('pintor', 'NCMS000'): 1, ('ser', 'VSIS3S0'): 1, ('muralista', 'AQ0CS0'): 1, ('diego_rivera', 'NP00000'): 1, ('frida_kahlo', 'NP00000'): 1, ('caso', 'NCMS000'): 1})
>>> [list(k) + [v] for k, v in res.iteritems()]
[['pintor', 'NCMS000', 1], ['ser', 'VSIS3S0', 1], ['diego_rivera', 'NP00000', 1], ['frida_kahlo', 'NP00000', 1], ['muralista', 'AQ0CS0', 1], ['caso', 'NCMS000', 1]]
</code></pre>
<p>如果希望值按排序顺序列出,请使用<code>.most_common()</code>而不是<code>.iteritems()</code>。你知道吗</p>