擅长:python、mysql、java
<pre><code>>>> data = Counter({('pintor', 'NCMS000'): 1, ('ser', 'VSIS3S0'): 1, ('muralista', 'AQ0CS0'): 1, ('diego_rivera', 'NP00000'): 1, ('frida_kahlo', 'NP00000'): 1, ('caso', 'NCMS000'): 1})
>>> [[k[0], k[1], v] for k, v in data.items()]
[['pintor', 'NCMS000', 1], ['ser', 'VSIS3S0', 1], ['diego_rivera', 'NP00000', 1], ['frida_kahlo', 'NP00000', 1], ['muralista', 'AQ0CS0', 1], ['caso', 'NCMS000', 1]]
</code></pre>
<p>或者使用元组解包的替代方法:</p>
<pre><code>>>> [[a, b, v] for (a, b), v in data.items()]
[['pintor', 'NCMS000', 1], ['ser', 'VSIS3S0', 1], ['diego_rivera', 'NP00000', 1], ['frida_kahlo', 'NP00000', 1], ['muralista', 'AQ0CS0', 1], ['caso', 'NCMS000', 1]]
</code></pre>