识别数组中的相似实例并合并它们

Question

我有一个数组，像这样。。。你知道吗

[['Abradolf Lincler', 4], ['Abradolf Lincler', 4], ['Scary Terry', 4], ['Abradolf Lincler', 4], ['Scary Terry', 4], ['Scary Terry', 4], ['Abradolf Lincler', 4], ['Scary Terry', 4], ['Scary Terry', 4], ['Abradolf Lincler', 4], ['Abradolf Lincler', 4], ['Abradolf Lincler', 4], ['Summer Smith', 4], ['Summer Smith', 4], ['Summer Smith', 4], ['Abradolf Lincler', 4], ['Summer Smith', 4], ['Summer Smith', 4]]

我希望能够扫描每个数组，如果数组中已经存在元素0，则合并它们并将第一个元素添加到一起。例如，有5个Summer Smith的例子。代码应该识别它是同一个玩家，因此将所有Summer Smith得分相加，使Summer Smith总得分为20。每个球员都应该这样。比如说

[['Harry',20], ['Jake', 16]]....

我试着。。。你知道吗

for array in arrays:
        if array[0] in [not sure what to do now]

Answer 1

考虑使用dictionary来跟踪每个玩家的得分总和：

scores = [['Abradolf Lincler', 4], ['Abradolf Lincler', 4], ['Scary Terry', 4], ['Abradolf Lincler', 4], ['Scary Terry', 4], ['Scary Terry', 4], ['Abradolf Lincler', 4], ['Scary Terry', 4], ['Scary Terry', 4], ['Abradolf Lincler', 4], ['Abradolf Lincler', 4], ['Abradolf Lincler', 4], ['Summer Smith', 4], ['Summer Smith', 4], ['Summer Smith', 4], ['Abradolf Lincler', 4], ['Summer Smith', 4], ['Summer Smith', 4]]

grouped_scores = {}
for name, score in scores:
    if name not in grouped_scores: grouped_scores[name] = score
    else: grouped_scores[name] += score

然后您可以以列表的形式返回结果：

merged_scores = [list(t) for t in grouped_scores.items()]
print(merged_scores)
# [['Summer Smith', 20], ['Scary Terry', 20], ['Abradolf Lincler', 32]]

Answer 2

更好地使用setdefault：

d={}
for x,y in arrays:
   d.setdefault(x,[]).append(y)
print(list(map(list,{k:sum(v) for k,v in d.items()}.items())))

输出：

[['Abradolf Lincler', 32], ['Scary Terry', 20], ['Summer Smith', 20]]

最佳defaultdict：

from collections import defaultdict
d=defaultdict(int)
for x,y in arrays:
   d[x]+=y
print(list(map(list,dict(d).items())))   

输出：

[['Abradolf Lincler', 32], ['Scary Terry', 20], ['Summer Smith', 20]]

Answer 3

我会用Counter

>>> from collections import Counter
>>> arrays = [['Abradolf Lincler', 4], ['Abradolf Lincler', 4], ['Scary Terry', 4], ['Abradolf Lincler', 4], ['Scary Terry', 4], ['Scary Terry', 4], ['Abradolf Lincler', 4], ['Scary Terry', 4], ['Scary Terry', 4], ['Abradolf Lincler', 4], ['Abradolf Lincler', 4], ['Abradolf Lincler', 4], ['Summer Smith', 4], ['Summer Smith', 4], ['Summer Smith', 4], ['Abradolf Lincler', 4], ['Summer Smith', 4], ['Summer Smith', 4]]
>>> result = Counter()
>>> for k, v in arrays:
...     result[k] += v
...
>>> result
Counter({'Abradolf Lincler': 32, 'Scary Terry': 20, 'Summer Smith': 20})