元组中有一些dict:
a = ({'row_n': 1, 'row_section': None, 'TM': 'FORD', 'article': 'F5OZ5311CA', 'description': '', 'size_measures_multi': {'unit': None, 'additional_field': None, 'size': ['1', '2', '1374,13']}},
{'row_n': 2, 'row_section': None, 'TM': 'FORD', 'article': 'FOVY7E395B', 'description': '', 'size_measures_multi': {'unit': None, 'additional_field': None, 'size': ['1', '3', '824,48']}}
{'row_n': 3, 'row_section': None, 'TM': 'FORD', 'article': 'RH170', 'description': '', 'size_measures_multi': {'unit': None, 'additional_field': None, 'size': ['1', '5', '412,24']}})
我需要按['size\u measures\u multi'][size]对这个dicts排序,并给出如下结果:
a = ({'row_n': 1, 'row_section': None, 'TM': 'FORD', 'article': 'F5OZ5311CA', 'description': '', 'size_measures_multi': {'unit': None, 'additional_field': None, 'size': ['1', '2', '1374,13']}},
{'row_n': 2, 'row_section': None, 'TM': 'FORD', 'article': 'FOVY7E395B', 'description': '', 'size_measures_multi': {'unit': None, 'additional_field': None, 'size': ['1', '3', '824,48']}}
{'row_n': 3, 'row_section': None, 'TM': 'FORD', 'article': 'RH170', 'description': '', 'size_measures_multi': {'unit': None, 'additional_field': None, 'size': ['1', '5', '412,24']}})
我试试这个
for i in a:
{x: sorted(i['size_measures_multi']['size']) for x in i.keys()}
但它给了我坏结果。你知道吗
我该怎么做。我将非常感谢你的帮助。你知道吗
只需使用sorted的关键参数:
输出
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