如何得到只搜索单词的结果python regex

Question

在python中，如何只获取与正则表达式匹配的单词？因为我试过的所有东西都会打印出找到绳子的那一行。你知道吗

正则表达式如下：

\b([1-9][0-9]{1,2})\.([0-9]{1,3})\.([0-9]{1,3})\.([0-9]{1,3})\/([0-9]{1,2})\b

它匹配IP+CIDR（例如12.0.0.0/8）

我搜索的文本如下：

04/30","172.18.186.0/24","172.18.185.0/24","172.18.177.16/28","dwefwf-1.RI-nc_wefwfwefwefpat_intweb_fe","172.18.176.16/28","edefwfwf
t_pat_infwef_fe","172.18.178.16/28","dwefwefwef-wefwffwefwefwef_dr_efwefeb_fe","172.18.176.80/28","DSwefwfH2. 
RI-nc_rat_dr_fweweb_fe","172.18.178.48/28","172.18.177.208/28","wefwef 
wefwtfweapp_fe","172.18.176.208/28","wfwfwefwefwefH2.RI-nwefwefdr_app_fe","172.18.177.192/28","de1dfwwf-1.wefewf","172.18.176.1
92/28","

Answer 1

我认为您的regexp工作正常。如果您想得到匹配的字符串，请使用^{}函数。像这样：

import re

regexp = r'\b([1-9][0-9]{1,2})\.([0-9]{1,3})\.([0-9]{1,3})\.([0-9]{1,3})\/([0-9]{1,2})\b'

text = '''04/30","172.18.186.0/24","172.18.185.0/24","172.18.177.16/28","dwefwf-1.RI-nc_wefwfwefwefpat_intweb_fe","172.18.176.16/28","edefwfwf
t_pat_infwef_fe","172.18.178.16/28","dwefwefwef-wefwffwefwefwef_dr_efwefeb_fe","172.18.176.80/28","DSwefwfH2. 
RI-nc_rat_dr_fweweb_fe","172.18.178.48/28","172.18.177.208/28","wefwef 
wefwtfweapp_fe","172.18.176.208/28","wfwfwefwefwefH2.RI-nwefwefdr_app_fe","172.18.177.192/28","de1dfwwf-1.wefewf","172.18.176.1
92/28","'''

for i in re.finditer(regexp, text):
    print i.group(0)

Answer 2

您应该修改regex，如下所示：

\b(([1-9][0-9]{1,2})\.([0-9]{1,3})\.([0-9]{1,3})\.([0-9]{1,3})\/([0-9]{1,2}))\b

然后提取第一个匹配的组：\1

演示：http://repl.it/R0W/1（运行需要一段时间）