无法在 if-loop 中使用 str 在 Python 3 中工作

Question

我写了一个分数计算器，你在里面放一个浮点数，然后根据你的得分得到一个分数。我的问题是，我相信我需要一个浮动（输入。。。但是如果你在盒子里写信，那就成了一个错误。。。你知道吗

def scoreGrade():
"""
Determine the grade from a score
"""
gradeA = "A"
gradeB = "B"
gradeC = "C"
gradeD = "D"
gradeF = "F"

score = float(input("Please write the score you got on the test, 0-10: "))
if score >= 9:
    print("You did really good, your grade is:", gradeA, ". Congratulations")
elif score >= 7:
    print("Your results are good. They earn you a:", gradeB, ". Better luck next time")
elif score >= 5:
    print("Not too bad. You got a:", gradeC)
elif score >= 4:
    print("That was close...:", gradeD)
elif score < 4:
    print("You need to step up and take the test again:", gradeF)
else:
    print("Grow up and write your score between 0 and 10")

如果你写了一些分数在0-10之间的东西，有没有办法去掉浮点数并打印最后一个语句？你知道吗

Answer 1

你能做到的

try:
    score = float(input("Please write the score you got on the test, 0-10: "))
except ValueError:
    print("Grow up and write your score between 0 and 10")
    scoreGrade()