擅长:python、mysql、java
<p>假设您有JSON结构,我将使用以下代码来解决您的问题:</p>
<pre><code># Suppose that json_response is the whole dictionary
entry_list = json_response["orderItems"]["entries"]
# Now for each entry in the list, you need to get the "href" field
hrefs = []
for entry in entry_list:
curr_href = entry["links"]["order"]["href"]
hrefs.append(curr_href)
</code></pre>
<p>为了正确访问字段,您需要注意字典结构。在使用此代码之前,请仔细阅读<a href="https://docs.python.org/3/tutorial/datastructures.html#dictionaries" rel="nofollow">Python3 documentation</a>中的词典。你知道吗</p>