擅长:python、mysql、java
<p>谢谢你的帮助,@uzzee,非常感谢。我不断地修补它,并能够用下面的代码提取所有图像URL的连续字符串。你知道吗</p>
<pre><code>resultsdict['images'] = sum([x['PictureURL'] for x in item['variations']['Pictures'][0]['VariationSpecificPictureSet']],[])
</code></pre>
<p>如果没有总和,它看起来像这样,并把整个列表。。。你知道吗</p>
<pre><code>resultsdict['images'] = [x['PictureURL'] for x in item['variations']['Pictures'][0]['VariationSpecificPictureSet']]
</code></pre>