我的原始词典包含以下形式的值:
[(0, {'T8': (0.3978349, 0), 'T9': (0.84942997, 0), 'T6': (1.1480641, 0), 'T7': (2.1811862, 0), 'T4': (2.016099, 0), 'T5': (1.5923926, 0), 'T2': (0.20877934, 0), 'T3': (-0.095536113, 0), 'T1': (0.89533514, 0), 'T10': (0.11839861, 0)}),
(11, {'T14': (-0.50686657, 0), 'T15': (-0.47247946, 0), 'T16': (-1.4296696, 0), 'T17': (-0.62257302, 0), 'T12': (0.61257166, 0), 'T13': (0.64874935, 0), 'T21': (-0.46329427, 0), 'T20': (-0.72244251, 0), 'T18': (-0.85425723, 0), 'T19': (-1.4788039, 0)})
(22, {'T25': (1.0260065, 0), 'T29': (2.1339068, 0), 'T28': (0.85323471, 0), 'T30': (2.4555078, 0), 'T23': (3.5931432, 0), 'T26': (0.52051008, 0), 'T32': (4.1754069, 0), 'T24': (1.2143329, 0), 'T27': (3.6651597, 0), 'T31': (3.1280968, 0)})]
这是10k
相同行文件中的几行。最初因为这个字典是无序的,所以我通过删除前导的T
值来使用key对它进行排序,现在它的排序形式是key
0 -> (values) 11-> (values) 22-> (values)
为了让我这么做
nd = {}
for qid, dinfo in res_scores.items(): #res_scores is the original unsorted dictionary
val = int(re.sub("\D", "", qid))
nd[val] = dinfo
sd = OrderedDict(sorted(nd.items(), key=lambda t: t[0]))
现在显示的输出是sd
的摘录。现在我需要对键的值进行排序,即:
{'T8': (0.3978349, 0), 'T9': (0.84942997, 0), 'T6': (1.1480641, 0), 'T7': (2.1811862, 0), 'T4': (2.016099, 0), 'T5': (1.5923926, 0), 'T2': (0.20877934, 0), 'T3': (-0.095536113, 0), 'T1': (0.89533514, 0), 'T10': (0.11839861, 0)}
通过删除前面的T值->
{1 : (0.89533514, 0), 2: (0.20877934, 0), 3: (-0.095536113, 0), 4: (2.016099, 0), 5: (1.5923926, 0), 6: (1.1480641, 0), 7: (2.1811862, 0), 8: (0.3978349, 0), 9: (0.84942997, 0), 10: (0.11839861, 0) }
如何在这里有效地对Python中嵌套字典的值进行排序?我尝试了一些类似问题的解决方案,但未能解决问题。任何帮助都将不胜感激。你知道吗
根据我对你的问题的理解,你可以试着把你的T值排序如下:
此外,如果您使用的是Python3.6+,那么字典将保持插入顺序,因此您不需要使用
OrderedDict
。你知道吗否则,可以这样使用
OrderedDict()
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