在使用ListViewSet时，如何对serializer MethodField上的序列化程序数据进行排序？

Question

我有一个类，比如GetStudentDetails，我正在使用一个序列化程序，序列化程序MethodField，比如posal\u address，我希望根据这个字段对结果进行排序

我尝试过添加ordering=（'posal\u address'，），由于它不是一个模型字段，所以遇到了错误。你知道吗

class GetStudentDetails(viewsets.GenericViewSet, mixins.ListModelMixin):
    model = Student
    queryset = Student.objects.all()
    serializer_class = StudentCreateSerializer
    filter_backends = 
    (filters.OrderingFilter,filters.DjangoFilterBackend,)

class StudentCreateSerializer(serializers.ModelSerializer):
    postal_address = serializers.SerializerMethodField()

    def get_postal_address(self, obj):
        return Address.objects.get(name=obj.name).address

    class Meta:
        model = Vehicle
        fields = ('name','city','state',postal_address')

class Address(models.Model):
    name=models.ForeignKey(Student, on_delete=models.CASCADE)
    address=models.CharField(max_length=60)

class Student(models.Model):
    name=models.CharField(max_length=45)
    city=models.CharField(max_length=10)
    state=models.CharField(max_length=10)

    def __str__(self):
        return name

实际结果：

[{"name":test",
"city":"abc",
"state":"def",
"postal_address":"abcdef"
},
{
"name":"test2",
"city":"aa",
"state":"bb",
"postal_address":"aabb"
}]

预期结果：

[{
"name":"test2",
"city":"aa",
"state":"bb",
"postal_address":"aabb"
},
{"name":test",
"city":"abc",
"state":"def",
"postal_address":"abcdef"
}]

Answer 1

我会尝试按您组合的两个字段排序：

ordering = ('city', 'state')

更新：

根据您更改的标准，尝试：

ordering = ('address_set__address', )

尽管根据this post，这种方法存在一些问题，答案者通过将排序硬编码到相关模型中来解决。所以在你的情况下：

class Address(models.Model):
    ...
    class Meta:
        ordering = ('address',)

然后在另一个模型/序列化程序中：

ordering = ('address_set', )