python分析字符串\r\n new lin

Question

我在分析行时遇到了一些问题。 实际上我把所有的东西都排成一行：

'test:[abc:123];something\r\nName=some name;phone no.: [123456]\r\nAddress: some address; another   address\r\n\r\n'

我想要这样的行：

test:[abc:123];something
Name=some name;phone no.: [123456]
Address: some address; another address

我试过了

#from ast import literal_eval
from ast import *
a = 'test:[abc:123];something\r\nName=some name;phone no.: [123456]\r\nAddress: some address; another address\r\n\r\n'
msg = literal_eval(a)
# and
msg = eval(a)

但我错了。有其他简单的方法解决这个问题吗？

Answer 1

kk = 'test:[abc:123];something\r\nName=some name;phone no.: [123456]\r\nAddress: some address; another address\r\n\r\n'
lk = "\n".join(kk.split("\r\n"))
print lk 

输出：

test:[abc:123];something
Name=some name;phone no.: [123456]
Address: some address; another   address