擅长:python、mysql、java
<p>我知道这不是最好的解决方案,但它将保持您列表中的顺序和独特元素:</p>
<pre><code>from collections import OrderedDict
l1=['TUDCAPL.CLM_NUM_CD',
'TUDCAPL.CRT_TS',
'TUDCAPL.CLM_NUM_CD',
'TUDCAPL.CRT_TS',
'TUDCAPJ.CLM_NUM_CD',
'TUDCAPJ.CRT_TS']
l2 = ['TUDCAPL.CLM_NUM_CD',
'TUDCAPL.CRT_TS']
d = OrderedDict(zip(l1,[None]*len(l1)))
d2 = OrderedDict(zip(l2,[None]*len(l2)))
d.update(d2)
print(d.keys()) # this will contain the resulting list of strings
</code></pre>