擅长:python、mysql、java
<p>简单的解决方案是使用标准过滤器<a href="https://docs.djangoproject.com/en/2.1/ref/models/querysets/#in" rel="nofollow noreferrer">__in=</a></p>
<pre><code>name_list = ['Bob', 'John', 'Rachel']
qs = People.objects.filter(name<b>__in</b>=name_list)</code></pre>