def find(inp, what):
matches = []
while what in inp:
idx = inp.find(what)
matches.append(inp[idx:])
# remove the previous pattern from the string
inp = inp[idx+len(what):]
return matches
import re
pattern = "VAJ"
re_str = pattern + "..." + "(" + pattern + "..." +"(" + pattern + "(.*)))"
regex = re.compile(re_str)
regex_extra = re.compile(pattern + ".*")
for line in open("data.txt"):
line = line.strip()
match = regex.search(line)
if match:
result = list()
result.append(match.group(0)) # entire regex match
result.append(match.group(1)) # outer regex parenthesis'ed group
result.append(match.group(2)) # middle regex parenthesis'ed group
# Most inner regex parenthesis'ed group contains rest of the line.
# Use this to find extra pattern.
#
the_rest = match.group(3)
match_extra = regex_extra.search(the_rest)
if match_extra: # If one more <pattern> in the rest of the line
result.append(match_extra.group(0)) # add it to the result list
# Output
print(result)
您可以使用^{} 来查找索引,即您的模式出现的位置。然后可以相应地对字符串进行切片。实现可以如下所示:
您可以将它与
find("AFVAJFLDVAJPQDVAJDSNJKVAJGHD", "VAJ")
一起使用。你知道吗这将调用具有子组匹配的正则表达式。 (https://docs.python.org/3.5/library/re.html#match-objects)
我的测试文件
data.txt
:Python代码:
输出:
文件的庞大性不是这段代码的问题,只要最长的一行在内存中放几次就可以了。你知道吗
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