擅长:python、mysql、java
<pre><code>dictExample = {
"name": "yes",
"age": 25,
"Check_Me": [
{"type": "code", "value": "001"},
{"type": "code", "value": "002"},
{"type": "code", "value": "003"},
{"type": "code", "value": "004"},
{"type": "code", "value": "005"}
],
}
if "007" not in [d['value'] for d in dictExample['Check_Me']]:
print("It works!")
else:
print("Failure...")
</code></pre>
<ul>
<li>只需迭代<code>Check_Me</code>并从字典中获取键<code>'value'</code>的所有值。你知道吗</li>
</ul>