<p>如果代码格式正确,这将变得容易得多:</p>
<pre><code>lst = [
{
'chin': [
(297, 322), (297, 339), (299, 356), (301, 373), (305, 390), (312, 405), (325, 415), (342, 418), (362, 420), (383, 421), (402, 421), (418, 415), (427, 403), (433, 387), (437, 370), (440, 352), (443, 335)
],
'left_eyebrow': [
(306, 296), (313, 282), (326, 276), (342, 276), (357, 281)
],
'right_eyebrow': [
(378, 283), (393, 278), (410, 281), (423, 289), (431, 303)
],
'nose_bridge': [
(366, 297), (365, 305), (364, 314), (363, 323)
],
'nose_tip': [
(347, 337), (355, 340), (364, 341), (373, 340), (382, 339)
],
'left_eye': [
(321, 304), (328, 296), (339, 296), (349, 304), (339, 305), (328, 305)
],
'right_eye': [
(386, 307), (397, 299), (407, 300), (415, 309), (407, 309), (396, 308)
],
'top_lip': [
(332, 363), (343, 355), (355, 351), (363, 353), (372, 352), (385, 357), (399, 366), (394, 365), (372, 359), (363, 359), (355, 359), (337, 362)
],
'bottom_lip': [
(399, 366), (385, 368), (372, 369), (363, 369), (354, 368), (343, 366), (332, 363), (337, 362), (354, 360), (363, 361), (372, 361), (394, 365)
]
}
]
</code></pre>
<p>它是一个包含字典的列表,其中每个键的值是一个元组列表。你知道吗</p>
<pre><code>for k in lst[0].keys():
print(lst[0][k])
</code></pre>
<p>要跳过<code>chin</code>:</p>
<pre><code>for k in lst[0].keys():
if k == "chin":
continue
print(lst[0][k])
</code></pre>