<p>您可以使用<a href="https://docs.python.org/3/library/functools.html#functools.reduce" rel="noreferrer">^{<cd1>}</a>和一个简单的列表理解来将dicts的列表展平</p>
<pre><code>>>> from functools import reduce
>>> data = [{'b': {'dislike': 'juice', 'favourite': 'coke'}, 'a': {'l': 'Apple', 'b': 'Milk', 'd': 'Meatball'}}, {'b': {'dislike': 'juice3', 'favourite': 'coke2'}, 'a': {'l': 'Apple1', 'b': 'Milk1', 'd': 'Meatball2'}}]
>>> [reduce(lambda x,y: {**x,**y},d.values()) for d in data]
>>> [{'dislike': 'juice', 'l': 'Apple', 'd': 'Meatball', 'b': 'Milk', 'favourite': 'coke'}, {'dislike': 'juice3', 'l': 'Apple1', 'd': 'Meatball2', 'b': 'Milk1', 'favourite': 'coke2'}]
</code></pre>
<p>时间基准如下:</p>
<pre><code>>>> import timeit
>>> setup = """
from functools import reduce
data = [{'b': {'dislike': 'juice', 'favourite': 'coke'}, 'a': {'l': 'Apple', 'b': 'Milk', 'd': 'Meatball'}}, {'b': {'dislike': 'juice3', 'favourite': 'coke2'}, 'a': {'l': 'Apple1', 'b': 'Milk1', 'd': 'Meatball2'}}]
"""
>>> min(timeit.Timer("[reduce(lambda x,y: {**x,**y},d.values()) for d in data]",setup=setup).repeat(3,1000000))
>>> 1.525032774952706
</code></pre>
<p>我机器上其他答案的时间基准</p>
<pre><code>>>> setup = """
data = [{'b': {'dislike': 'juice', 'favourite': 'coke'}, 'a': {'l': 'Apple', 'b': 'Milk', 'd': 'Meatball'}}, {'b': {'dislike': 'juice3', 'favourite': 'coke2'}, 'a': {'l': 'Apple1', 'b': 'Milk1', 'd': 'Meatball2'}}]
"""
>>> min(timeit.Timer("[{k: v for x in d.values() for k, v in x.items()} for d in data]",setup=setup).repeat(3,1000000))
>>> 2.2488374650129117
>>> min(timeit.Timer("[{k: x[k] for x in d.values() for k in x} for d in data]",setup=setup).repeat(3,1000000))
>>> 1.8990078769857064
>>> code = """
L = []
for d in data:
temp = {}
for key in d:
temp.update(d[key])
L.append(temp)
"""
>>> min(timeit.Timer(code,setup=setup).repeat(3,1000000))
>>> 1.4258553800173104
>>> setup = """
from itertools import chain
data = [{'b': {'dislike': 'juice', 'favourite': 'coke'}, 'a': {'l': 'Apple', 'b': 'Milk', 'd': 'Meatball'}}, {'b': {'dislike': 'juice3', 'favourite': 'coke2'}, 'a': {'l': 'Apple1', 'b': 'Milk1', 'd': 'Meatball2'}}]
"""
>>> min(timeit.Timer("[dict(chain(*map(dict.items, d.values()))) for d in data]",setup=setup).repeat(3,1000000))
>>> 3.774383604992181
</code></pre>