如何在每个单词之间输出一个空格的字符串

Question

例如，如果输入I love dogs，则需要如下所示：

I  l o v e  d o g s

此代码不执行我需要它执行的操作：

def spaceitout(source):
    pile = ""
    for letter in source:
        pile = pile+letter
        print pile
    print pile

Answer 1

字母间距：

def spaceitout(source, count): 
    return (' '*count).join([letter for letter in source.replace(' ','')])

字距：

def spaceitout(source, count):
    return (' '*count).join(source.split())

所有字符之间的空格：

def spaceitout(source, count): 
    return (''.join([c + (' '*count) for c in source]).strip())

Answer 2

def evenly_spaced(string_,space_= 1):

    import re

    return (' '*space_).join([c for c in re.split(r'(\w)',string_) if c.isalpha()])

print(evenly_spaced(" This a long story ",2))

T  h  i  s  a  l  o  n  g  s  t  o  r  y

Answer 3

简单的答案是：

def spaceitout(source):
    pile = ""
    for letter in source:
        pile = pile + letter + " "
    pile = pile[:-1] #Strip last extraneous space.
    print pile